What is the vertices ((x+4)^2)/9+((y-1)^2)/4 =1 ?

The vertices ((x+4)^2)/9+((y-1)^2)/4 =1 is (-1,1),(-7,1)

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vertices ((x+4)^2)/9+((y-1)^2)/4 =1

vertices

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

(- 1, 1), (- 7, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (- 4, 1), a = 3, b = 2

(- 4 + 3, 1), (- 4 - 3, 1)

Refine

(- 1, 1), (- 7, 1)

25 x^{2} + 9 y^{2} + 50 x - 108 y + 124 = 0

25 x^{2} + 4 y^{2} - 250 x - 16 y + 541 = 0

3 x^{2} + 4 y^{2} = 12

\frac{x ^{2}}{6 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

\frac{x ^{2}}{49} + \frac{y ^{2}}{4} = 1

What is the vertices ((x+4)^2)/9+((y-1)^2)/4 =1 ?
The vertices ((x+4)^2)/9+((y-1)^2)/4 =1 is (-1,1),(-7,1)