What is the vertices 9x^2+18x+4y^2-24y+9=0 ?

The vertices 9x^2+18x+4y^2-24y+9=0 is (-1,6),(-1,0)

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vertices 9x^2+18x+4y^2-24y+9=0

vertices

9 x^{2} + 18 x + 4 y^{2} - 24 y + 9 = 0

(- 1, 6), (- 1, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 18 x + 4 y^{2} - 24 y + 9 = 0 :

Ellipse with center

(h, k) = (- 1, 3), b = 3, a = 2

(- 1, 3 + 3), (- 1, 3 - 3)

Refine

(- 1, 6), (- 1, 0)

3 x^{2} + 12 y^{2} - 6 x - 48 y + 33 = 0

36 x^{2} + 25 y^{2} = 900

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

x^{2} + y^{2} + 8 x = 32

4 x^{2} + 9 y^{2} - 16 x + 36 y + 16 = 0

What is the vertices 9x^2+18x+4y^2-24y+9=0 ?
The vertices 9x^2+18x+4y^2-24y+9=0 is (-1,6),(-1,0)