What is the vertices 64x^2+9y^2=576 ?

The vertices 64x^2+9y^2=576 is (0,8),(0,-8)

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vertices 64x^2+9y^2=576

vertices

64 x^{2} + 9 y^{2} = 576

(0, 8), (0, - 8)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

64 x^{2} + 9 y^{2} = 576 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 3

(0, 0 + 8), (0, 0 - 8)

Refine

(0, 8), (0, - 8)

x^{2} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

\frac{x ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

25 x^{2} + 144 y^{2} = 900

4 x^{2} + 16 y^{2} - 16 x - 48 = 0

What is the vertices 64x^2+9y^2=576 ?
The vertices 64x^2+9y^2=576 is (0,8),(0,-8)