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Popular >

vertices 4x^2+9y^2=1

Solution

vertices

4 x^{2} + 9 y^{2} = 1

Solution

(\frac{1}{2}, 0), (- \frac{1}{2}, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = \frac{1}{2}, b = \frac{1}{3}

(0 + \frac{1}{2}, 0), (0 - \frac{1}{2}, 0)

Refine

(\frac{1}{2}, 0), (- \frac{1}{2}, 0)

Popular Examples

vertices 4x^2+y^2=4 vertices

4 x^{2} + y^{2} = 4

vertices 36x^2+9y^2+48x-36y+43=0 vertices

36 x^{2} + 9 y^{2} + 48 x - 36 y + 43 = 0

vertices 16x^2-96x+4y^2=-80 vertices

16 x^{2} - 96 x + 4 y^{2} = - 80

vertices x^2+16y^2-64=0 vertices

x^{2} + 16 y^{2} - 64 = 0

vertices ((x-7)^2)/4+((y+3)^2)/(16)=1 vertices

\frac{( x - 7 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

Frequently Asked Questions (FAQ)

What is the vertices 4x^2+9y^2=1 ?
The vertices 4x^2+9y^2=1 is (1/2 ,0),(-1/2 ,0)