What is the vertices ((x-1)^2)/(45)+((y-2)^2)/(20)=1 ?

The vertices ((x-1)^2)/(45)+((y-2)^2)/(20)=1 is (1+3sqrt(5),2),(1-3sqrt(5),2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices ((x-1)^2)/(45)+((y-2)^2)/(20)=1

vertices

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1

(1 + 35, 2), (1 - 35, 2)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1 :

Ellipse with center

(h, k) = (1, 2), a = 35, b = 25

(1 + 35, 2), (1 - 35, 2)

4 x^{2} + 9 y^{2} - 16 x - 18 y - 11 = 0

x^{2} + 3 y^{2} = 6

x^{2} + 3 y^{2} - 6 x + 6 y = 0

7 x^{2} + 9 y^{2} = 63

\frac{x ^{2}}{81} + \frac{y ^{2}}{225} = 1

What is the vertices ((x-1)^2)/(45)+((y-2)^2)/(20)=1 ?
The vertices ((x-1)^2)/(45)+((y-2)^2)/(20)=1 is (1+3sqrt(5),2),(1-3sqrt(5),2)