What is the vertices (x^2)/(100)+(y^2)/(25)=1 ?

The vertices (x^2)/(100)+(y^2)/(25)=1 is (10,0),(-10,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (x^2)/(100)+(y^2)/(25)=1

vertices

\frac{x ^{2}}{100} + \frac{y ^{2}}{25} = 1

(10, 0), (- 10, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 5

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

12.92 x^{2} + 0.07 y^{2} - 36 = 0

15 x^{2} + 16 y^{2} = 240

\frac{x ^{2}}{49} + \frac{( y - 3 ) ^{2}}{16} = 1

16 (x - 4)^{2} + 25 (y + 2)^{2} = 400

3 x^{2} + 4 y^{2} - 12 x = 36

What is the vertices (x^2)/(100)+(y^2)/(25)=1 ?
The vertices (x^2)/(100)+(y^2)/(25)=1 is (10,0),(-10,0)