en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 4x^2+y^2=4x

Solution

vertices

4 x^{2} + y^{2} = 4 x

Solution

(\frac{1}{2}, 1), (\frac{1}{2}, - 1)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

4 x^{2} + y^{2} = 4 x :

Ellipse with center

(h, k) = (\frac{1}{2}, 0), b = 1, a = \frac{1}{2}

(\frac{1}{2}, 0 + 1), (\frac{1}{2}, 0 - 1)

Refine

(\frac{1}{2}, 1), (\frac{1}{2}, - 1)

Popular Examples

vertices 4x^2+4x+y^2=0 vertices

4 x^{2} + 4 x + y^{2} = 0

vertices ((x^2))/7+((y^2))/(16)=1 vertices

\frac{( x ^{2} )}{7} + \frac{( y ^{2} )}{16} = 1

vertices ((x+1)^2)/9+((y-3)^2)/(10)=1 vertices

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{10} = 1

vertices (x^2)/9+((y-4)^2)/7 =1 vertices

\frac{x ^{2}}{9} + \frac{( y - 4 ) ^{2}}{7} = 1

vertices ((x-3)^2)/4+((y+2)^2)/1 =1 vertices

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{1} = 1

Frequently Asked Questions (FAQ)

What is the vertices 4x^2+y^2=4x ?
The vertices 4x^2+y^2=4x is (1/2 ,1),(1/2 ,-1)