What is the answer to solvefor f,f(x)^2(1/(2+x))=-1 ?

The answer to solvefor f,f(x)^2(1/(2+x))=-1 is f=(-2-x)/(x^2);\quad x\ne-2,x\ne 0

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solvefor f,f(x)^2(1/(2+x))=-1

solve for

f, f (x)^{2} (\frac{1}{2 + x}) = - 1

f = \frac{- 2 - x}{x ^{2}}; x \neq = - 2, x \neq = 0

Solution steps

f x^{2} (\frac{1}{2 + x}) = - 1

Simplify

x^{2} (\frac{1}{2 + x}) : \frac{x ^{2}}{2 + x}

f \frac{x ^{2}}{2 + x} = - 1

Multiply both sides by

2 + x

x^{2} f = - 2 - x; x \neq = - 2

Divide both sides by

x^{2}; x \neq = - 2, x \neq = 0

f = \frac{- 2 - x}{x ^{2}}; x \neq = - 2, x \neq = 0

8 x^{2} + 12 y = 0

y^{2} = x + 100

(x + 1)^{2} = - 8 (y - 2)

x = 5 y - y^{2}

y^{2} - 3 x + 5 = 0

What is the answer to solvefor f,f(x)^2(1/(2+x))=-1 ?
The answer to solvefor f,f(x)^2(1/(2+x))=-1 is f=(-2-x)/(x^2);\quad x\ne-2,x\ne 0