What is the vertices 9x^2+4y^2-18x-16y-11=0 ?

The vertices 9x^2+4y^2-18x-16y-11=0 is (1,5),(1,-1)

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vertices 9x^2+4y^2-18x-16y-11=0

vertices

9 x^{2} + 4 y^{2} - 18 x - 16 y - 11 = 0

(1, 5), (1, - 1)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 4 y^{2} - 18 x - 16 y - 11 = 0 :

Ellipse with center

(h, k) = (1, 2), b = 3, a = 2

(1, 2 + 3), (1, 2 - 3)

Refine

(1, 5), (1, - 1)

4 x^{2} + 9 y^{2} = 25

\frac{( x + 3 ) ^{2}}{26} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

4 x^{2} + y^{2} - 32 x + 16 y + 124 = 0

(x - 2)^{2} + 4 (y - 3)^{2} = 4

What is the vertices 9x^2+4y^2-18x-16y-11=0 ?
The vertices 9x^2+4y^2-18x-16y-11=0 is (1,5),(1,-1)