What is the vertices ((x-1)^2)/9+((y-5)^2)/(25)=1 ?

The vertices ((x-1)^2)/9+((y-5)^2)/(25)=1 is (1,10),(1,0)

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vertices ((x-1)^2)/9+((y-5)^2)/(25)=1

vertices

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 5 ) ^{2}}{25} = 1

(1, 10), (1, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 5 ) ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (1, 5), b = 5, a = 3

(1, 5 + 5), (1, 5 - 5)

Refine

(1, 10), (1, 0)

2 \frac{( x - 6 ) ^{2}}{3} + 7 \frac{( y + 4 ) ^{2}}{4} = 1

\frac{x ^{2}}{96} + \frac{y ^{2}}{100} = 1

\frac{( x + 4 ) ^{2}}{24} + \frac{( y + 2 ) ^{2}}{49} = 1

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{4} = 1

\frac{x ^{2}}{81} + \frac{y ^{2}}{9} = 1

What is the vertices ((x-1)^2)/9+((y-5)^2)/(25)=1 ?
The vertices ((x-1)^2)/9+((y-5)^2)/(25)=1 is (1,10),(1,0)