What is the vertices 16x^2-64x+9y^2-54y=-1 ?

The vertices 16x^2-64x+9y^2-54y=-1 is (2,7),(2,-1)

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vertices 16x^2-64x+9y^2-54y=-1

vertices

16 x^{2} - 64 x + 9 y^{2} - 54 y = - 1

(2, 7), (2, - 1)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

16 x^{2} - 64 x + 9 y^{2} - 54 y = - 1 :

Ellipse with center

(h, k) = (2, 3), b = 4, a = 3

(2, 3 + 4), (2, 3 - 4)

Refine

(2, 7), (2, - 1)

\frac{x ^{2}}{15} + \frac{y ^{2}}{16} = 1

36 x^{2} + 9 y^{2} + 36 y - 288 = 0

36 x^{2} + 16 y^{2} - 64 y - 512 = 0

7 x^{2} + 16 y^{2} = 112

9 x^{2} + 49 y^{2} = 441

What is the vertices 16x^2-64x+9y^2-54y=-1 ?
The vertices 16x^2-64x+9y^2-54y=-1 is (2,7),(2,-1)