What is the vertices (x^2)/(121)+(y/1)^2=1 ?

The vertices (x^2)/(121)+(y/1)^2=1 is (11,0),(-11,0)

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vertices (x^2)/(121)+(y/1)^2=1

vertices

\frac{x ^{2}}{121} + (\frac{y}{1})^{2} = 1

(11, 0), (- 11, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{121} + (\frac{y}{1})^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 11, b = 1

(0 + 11, 0), (0 - 11, 0)

Refine

(11, 0), (- 11, 0)

\frac{( x + 4 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{16} = 1

6 x^{2} + 9 y^{2} - 54 = 0

+ 36 x^{2} + y^{2} = 36

\frac{( x + 5 ) ^{2}}{9} + \frac{y ^{2}}{4} = 1

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{9} = 1

What is the vertices (x^2)/(121)+(y/1)^2=1 ?
The vertices (x^2)/(121)+(y/1)^2=1 is (11,0),(-11,0)