What is the vertices 81x^2+36y^2=2916 ?

The vertices 81x^2+36y^2=2916 is (0,9),(0,-9)

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vertices 81x^2+36y^2=2916

vertices

81 x^{2} + 36 y^{2} = 2916

(0, 9), (0, - 9)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

81 x^{2} + 36 y^{2} = 2916 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 6

(0, 0 + 9), (0, 0 - 9)

Refine

(0, 9), (0, - 9)

(x)^{2} + \frac{( y - 1 ) ^{2}}{4} = 1

16 (x - 1)^{2} + 25 (y - 4)^{2} = 400

25 x^{2} + 16 y^{2} - 50 x + 64 y - 311 = 0

16 x^{2} + 36 y^{2} - 256 x + 448 = 0

9 x^{2} + 25 y^{2} - 36 x - 50 y + 60 = 0

What is the vertices 81x^2+36y^2=2916 ?
The vertices 81x^2+36y^2=2916 is (0,9),(0,-9)