What is the vertices 9x^2+36y^2+36x-216y+36=0 ?

The vertices 9x^2+36y^2+36x-216y+36=0 is (4,3),(-8,3)

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vertices 9x^2+36y^2+36x-216y+36=0

vertices

9 x^{2} + 36 y^{2} + 36 x - 216 y + 36 = 0

(4, 3), (- 8, 3)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

9 x^{2} + 36 y^{2} + 36 x - 216 y + 36 = 0 :

Ellipse with center

(h, k) = (- 2, 3), a = 6, b = 3

(- 2 + 6, 3), (- 2 - 6, 3)

Refine

(4, 3), (- 8, 3)

9 x^{2} + 6 y^{2} + 36 y = 0

\frac{x ^{2}}{2} + \frac{y ^{2}}{3} = 1

x^{2} + 4 y^{2} - 6 x - 16 y = 36

(\frac{x + 5}{4})^{2} + (\frac{y - 4}{16})^{2} = 1

x^{2} + 25 y^{2} = 25

What is the vertices 9x^2+36y^2+36x-216y+36=0 ?
The vertices 9x^2+36y^2+36x-216y+36=0 is (4,3),(-8,3)