What is the foci 64x^2+100y^2+768x-600y-3196=0 ?

The foci 64x^2+100y^2+768x-600y-3196=0 is (0,3),(-12,3)

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foci 64x^2+100y^2+768x-600y-3196=0

foci

64 x^{2} + 100 y^{2} + 768 x - 600 y - 3196 = 0

(0, 3), (- 12, 3)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

64 x^{2} + 100 y^{2} + 768 x - 600 y - 3196 = 0 :

Ellipse with center

(h, k) = (- 6, 3), a = 10, b = 8

(- 6 + c, 3), (- 6 - c, 3)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(- 6 + 6, 3), (- 6 - 6, 3)

Refine

(0, 3), (- 12, 3)

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

3 x^{2} + y^{2} - 24 x + 39 = 0

9 x^{2} - 18 x + 4 y^{2} = 27

41 x^{2} + 16 y^{2} + 246 x - 192 y + 289 = 0

What is the foci 64x^2+100y^2+768x-600y-3196=0 ?
The foci 64x^2+100y^2+768x-600y-3196=0 is (0,3),(-12,3)