What is the foci 25x^2+16y^2+50x-64y-311=0 ?

The foci 25x^2+16y^2+50x-64y-311=0 is (-1,5),(-1,-1)

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foci 25x^2+16y^2+50x-64y-311=0

foci

25 x^{2} + 16 y^{2} + 50 x - 64 y - 311 = 0

(- 1, 5), (- 1, - 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 16 y^{2} + 50 x - 64 y - 311 = 0 :

Ellipse with center

(h, k) = (- 1, 2), b = 5, a = 4

(- 1, 2 + c), (- 1, 2 - c)

Compute

c :

c = 5^{2} - 4^{2} : 3

(- 1, 2 + 3), (- 1, 2 - 3)

Refine

(- 1, 5), (- 1, - 1)

x^{2} + 8 (y + 5)^{2} = 20

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} > 1

4 x^{2} + 9 y^{2} + 8 x - 36 y + 4 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{a ^{2}} = 1

What is the foci 25x^2+16y^2+50x-64y-311=0 ?
The foci 25x^2+16y^2+50x-64y-311=0 is (-1,5),(-1,-1)