What is the foci (x^2)/(16)+(y^2)/(81)=1 ?

The foci (x^2)/(16)+(y^2)/(81)=1 is (0,sqrt(65)),(0,-sqrt(65))

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foci (x^2)/(16)+(y^2)/(81)=1

foci

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

(0, 65), (0, - 65)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 9^{2} - 4^{2} : 65

(0, 0 + 65), (0, 0 - 65)

Refine

(0, 65), (0, - 65)

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

\frac{( x - 4 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

\frac{( x + 1 ) ^{2}}{28} + \frac{( y + 5 ) ^{2}}{23} = 1

x^{2} - 8 x + 25 y^{2} - 100 y + 91 = 0

What is the foci (x^2)/(16)+(y^2)/(81)=1 ?
The foci (x^2)/(16)+(y^2)/(81)=1 is (0,sqrt(65)),(0,-sqrt(65))