What is (y+4)=4*3.5*(x-3)^2 ?

The solution to (y+4)=4*3.5*(x-3)^2 is Parabola with (h,k)=(3,-4),p= 1/56

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(y+4)=43.5(x-3)^2

(y + 4) = 4 \cdot 3.5 \cdot (x - 3)^{2}

(h, k) = (3, - 4), p = \frac{1}{56}

Solution steps

(y + 4) = 4 \cdot 3.5 (x - 3)^{2}

Rewrite

(y + 4) = 4 \cdot 3.5 (x - 3)^{2}

in the standard form:

4 \cdot \frac{1}{56} (y - (- 4)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 4), p = \frac{1}{56}

x - y^{2} = 7

y^{2} - 4 y + 6 x - 8 = 0

x = y^{2} - y + 1

y^{2} - 2 x + 6 y + 3 = 0

x^{2} - 14 x + 4 y + 29 = 0

What is (y+4)=4*3.5*(x-3)^2 ?
The solution to (y+4)=4*3.5*(x-3)^2 is Parabola with (h,k)=(3,-4),p= 1/56