What is the foci 9x^2+25y^2+18x+150y+9=0 ?

The foci 9x^2+25y^2+18x+150y+9=0 is (3,-3),(-5,-3)

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foci 9x^2+25y^2+18x+150y+9=0

foci

9 x^{2} + 25 y^{2} + 18 x + 150 y + 9 = 0

(3, - 3), (- 5, - 3)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 18 x + 150 y + 9 = 0 :

Ellipse with center

(h, k) = (- 1, - 3), a = 5, b = 3

(- 1 + c, - 3), (- 1 - c, - 3)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 1 + 4, - 3), (- 1 - 4, - 3)

Refine

(3, - 3), (- 5, - 3)

\frac{x ^{2}}{4} + \frac{y ^{2}}{49} = 1

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

x^{2} + y^{2} + 2 x = 3 y

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y + 5 ) ^{2}}{9} = 1

What is the foci 9x^2+25y^2+18x+150y+9=0 ?
The foci 9x^2+25y^2+18x+150y+9=0 is (3,-3),(-5,-3)