What is the foci 4x^2+49y^2=196 ?

The foci 4x^2+49y^2=196 is (3sqrt(5),0),(-3sqrt(5),0)

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foci 4x^2+49y^2=196

foci

4 x^{2} + 49 y^{2} = 196

(35, 0), (- 35, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 49 y^{2} = 196 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} - 2^{2} : 35

(0 + 35, 0), (0 - 35, 0)

Refine

(35, 0), (- 35, 0)

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

16 x^{2} - 96 x + 4 y^{2} = - 80

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{25} = 1

What is the foci 4x^2+49y^2=196 ?
The foci 4x^2+49y^2=196 is (3sqrt(5),0),(-3sqrt(5),0)