What is the foci (x^2)/2+(y^2)/4 =1 ?

The foci (x^2)/2+(y^2)/4 =1 is (0,sqrt(2)),(0,-sqrt(2))

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foci (x^2)/2+(y^2)/4 =1

foci

\frac{x ^{2}}{2} + \frac{y ^{2}}{4} = 1

(0, 2), (0, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{2} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 2, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} - 2^{2} : 2

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

x^{2} + \frac{y ^{2}}{4} = 1

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

\frac{x ^{2}}{4} + y^{2} = 1

x^{2} + \frac{1}{3} y^{2} = x + y

\frac{( x - 4 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1

What is the foci (x^2)/2+(y^2)/4 =1 ?
The foci (x^2)/2+(y^2)/4 =1 is (0,sqrt(2)),(0,-sqrt(2))