What is the foci 4x^2+9y^2-32x-36y+64=0 ?

The foci 4x^2+9y^2-32x-36y+64=0 is (4+sqrt(5),2),(4-sqrt(5),2)

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foci 4x^2+9y^2-32x-36y+64=0

foci

4 x^{2} + 9 y^{2} - 32 x - 36 y + 64 = 0

(4 + 5, 2), (4 - 5, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} - 32 x - 36 y + 64 = 0 :

Ellipse with center

(h, k) = (4, 2), a = 3, b = 2

(4 + c, 2), (4 - c, 2)

Compute

c :

c = 3^{2} - 2^{2} : 5

(4 + 5, 2), (4 - 5, 2)

4 x^{2} + y^{2} = 4

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{3. 2 ^{2}} + \frac{y ^{2}}{2.4 8 ^{2}} = 1

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{9} = 1

What is the foci 4x^2+9y^2-32x-36y+64=0 ?
The foci 4x^2+9y^2-32x-36y+64=0 is (4+sqrt(5),2),(4-sqrt(5),2)