What is the foci 16x^2-96x+9y^2=0 ?

The foci 16x^2-96x+9y^2=0 is (3,sqrt(7)),(3,-sqrt(7))

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foci 16x^2-96x+9y^2=0

foci

16 x^{2} - 96 x + 9 y^{2} = 0

(3, 7), (3, - 7)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

16 x^{2} - 96 x + 9 y^{2} = 0 :

Ellipse with center

(h, k) = (3, 0), b = 4, a = 3

(3, 0 + c), (3, 0 - c)

Compute

c :

c = 4^{2} - 3^{2} : 7

(3, 0 + 7), (3, 0 - 7)

Refine

(3, 7), (3, - 7)

x^{2} + 4 y^{2} - 6 x - 16 y + 21 = 0

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

x^{2} + 8 y^{2} = 32

25 x^{2} + y^{2} - 100 x + 8 y + 91 = 0

9 x^{2} + 36 y^{2} = 324

What is the foci 16x^2-96x+9y^2=0 ?
The foci 16x^2-96x+9y^2=0 is (3,sqrt(7)),(3,-sqrt(7))