What is the foci (x^2}{34}+\frac{y^2)/9 =1 ?

The foci (x^2}{34}+\frac{y^2)/9 =1 is (5,0),(-5,0)

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foci (x^2}{34}+\frac{y^2)/9 =1

foci

\frac{x ^{2}}{34} + \frac{y ^{2}}{9} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{34} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 34, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 34^{2} - 3^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

x^{2} + 4 y^{2} - 4 x = 0

9 x^{2} + 4 y^{2} - 36 x + 40 y + 100 = 0

x^{2} + y^{2} - 2 y = 0

\frac{x ^{2}}{12} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{25} = 1

What is the foci (x^2}{34}+\frac{y^2)/9 =1 ?
The foci (x^2}{34}+\frac{y^2)/9 =1 is (5,0),(-5,0)