What is the foci 9x^2+25y^2-100y-125=0 ?

The foci 9x^2+25y^2-100y-125=0 is (4,2),(-4,2)

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foci 9x^2+25y^2-100y-125=0

foci

9 x^{2} + 25 y^{2} - 100 y - 125 = 0

(4, 2), (- 4, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} - 100 y - 125 = 0 :

Ellipse with center

(h, k) = (0, 2), a = 5, b = 3

(0 + c, 2), (0 - c, 2)

Compute

c :

c = 5^{2} - 3^{2} : 4

(0 + 4, 2), (0 - 4, 2)

Refine

(4, 2), (- 4, 2)

3 x^{2} + 4 y^{2} = 12

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

\frac{( x - 1 ) ^{2}}{45} + \frac{y ^{2}}{54} = 1

What is the foci 9x^2+25y^2-100y-125=0 ?
The foci 9x^2+25y^2-100y-125=0 is (4,2),(-4,2)