What is the foci 25x^2+16y^2+100x-96y-156=0 ?

The foci 25x^2+16y^2+100x-96y-156=0 is (-2,6),(-2,0)

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foci 25x^2+16y^2+100x-96y-156=0

foci

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

(- 2, 6), (- 2, 0)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0 :

Ellipse with center

(h, k) = (- 2, 3), b = 5, a = 4

(- 2, 3 + c), (- 2, 3 - c)

Compute

c :

c = 5^{2} - 4^{2} : 3

(- 2, 3 + 3), (- 2, 3 - 3)

Refine

(- 2, 6), (- 2, 0)

2 x^{2} + 4 y^{2} - 8 x - 4 y - 15 = 0

3 x^{2} + y^{2} = 9

16 x^{2} + 81 y^{2} = 81

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

\frac{( x + 3 ) ^{2}}{49} + \frac{y ^{2}}{36} = 1

What is the foci 25x^2+16y^2+100x-96y-156=0 ?
The foci 25x^2+16y^2+100x-96y-156=0 is (-2,6),(-2,0)