What is the foci (x^2)/(81)+(y^2)/(64)=1 ?

The foci (x^2)/(81)+(y^2)/(64)=1 is (sqrt(17),0),(-sqrt(17),0)

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foci (x^2)/(81)+(y^2)/(64)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

(17, 0), (- 17, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 8^{2} : 17

(0 + 17, 0), (0 - 17, 0)

Refine

(17, 0), (- 17, 0)

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

36 x^{2} + 9 y^{2} + 48 x - 36 y + 43 = 0

4 x^{2} + 9 y^{2} - 18 y - 27 = 0

9 x^{2} + 36 x + y^{2} + 2 y + 36 = 0

\frac{( x - 4 ) ^{2}}{9} + (y + 3)^{2} = 1

What is the foci (x^2)/(81)+(y^2)/(64)=1 ?
The foci (x^2)/(81)+(y^2)/(64)=1 is (sqrt(17),0),(-sqrt(17),0)