What is the foci 81x^2+9y^2=9 ?

The foci 81x^2+9y^2=9 is (0,(2sqrt(2))/3),(0,-(2sqrt(2))/3)

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foci 81x^2+9y^2=9

foci

81 x^{2} + 9 y^{2} = 9

(0, \frac{2 2}{3}), (0, - \frac{2 2}{3})

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

81 x^{2} + 9 y^{2} = 9 :

Ellipse with center

(h, k) = (0, 0), b = 1, a = \frac{1}{3}

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} - (\frac{1}{3})^{2} : \frac{2 2}{3}

(0, 0 + \frac{2 2}{3}), (0, 0 - \frac{2 2}{3})

Refine

(0, \frac{2 2}{3}), (0, - \frac{2 2}{3})

\frac{x ^{2}}{16} + \frac{( y - 4 ) ^{2}}{1} = 1

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 6 ) ^{2}}{121} = 1

\frac{( x + 7 ) ^{2}}{8} + \frac{( y - 10 ) ^{2}}{13} = 1

\frac{( x - 1 ) ^{2}}{49} + \frac{( y - 3 ) ^{2}}{36} = 1

4 x^{2} + y^{2} - 32 x + 16 y + 124 = 0

What is the foci 81x^2+9y^2=9 ?
The foci 81x^2+9y^2=9 is (0,(2sqrt(2))/3),(0,-(2sqrt(2))/3)