What is the foci 4x^2+24x+25y^2+200y+336=0 ?

The foci 4x^2+24x+25y^2+200y+336=0 is (-3+sqrt(21),-4),(-3-sqrt(21),-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 4x^2+24x+25y^2+200y+336=0

foci

4 x^{2} + 24 x + 25 y^{2} + 200 y + 336 = 0

(- 3 + 21, - 4), (- 3 - 21, - 4)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 24 x + 25 y^{2} + 200 y + 336 = 0 :

Ellipse with center

(h, k) = (- 3, - 4), a = 5, b = 2

(- 3 + c, - 4), (- 3 - c, - 4)

Compute

c :

c = 5^{2} - 2^{2} : 21

(- 3 + 21, - 4), (- 3 - 21, - 4)

\frac{( x + 1 ) ^{2}}{10} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x ) ^{2}}{44} + \frac{y ^{2}}{125} = 1

2 x^{2} + 8 y^{2} = 16

64 x^{2} + y^{2} = 64

25 x^{2} + 9 y^{2} - 100 x - 54 y - 44 = 0

What is the foci 4x^2+24x+25y^2+200y+336=0 ?
The foci 4x^2+24x+25y^2+200y+336=0 is (-3+sqrt(21),-4),(-3-sqrt(21),-4)