What is the foci (x^2)/(16)+y^2=1 ?

The foci (x^2)/(16)+y^2=1 is (sqrt(15),0),(-sqrt(15),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(16)+y^2=1

foci

\frac{x ^{2}}{16} + y^{2} = 1

(15, 0), (- 15, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{16} + y^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} - 1^{2} : 15

(0 + 15, 0), (0 - 15, 0)

Refine

(15, 0), (- 15, 0)

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

\frac{( y + 3 ) ^{2}}{144} + \frac{( x + 2 ) ^{2}}{25} = 1

5 x^{2} + 9 y^{2} - 20 x + 54 y + 56 = 0

What is the foci (x^2)/(16)+y^2=1 ?
The foci (x^2)/(16)+y^2=1 is (sqrt(15),0),(-sqrt(15),0)