What is the foci (x^2)/(25)+(y^2)/(21)=1 ?

The foci (x^2)/(25)+(y^2)/(21)=1 is (2,0),(-2,0)

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foci (x^2)/(25)+(y^2)/(21)=1

foci

\frac{x ^{2}}{25} + \frac{y ^{2}}{21} = 1

(2, 0), (- 2, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{21} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 21

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} - 21^{2} : 2

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

\frac{( x + 2 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

81 x^{2} + 49 y^{2} = 3969

25 x^{2} + 4 y^{2} + 100 x = 0

\frac{x ^{2}}{9 ^{2}} + \frac{y ^{2}}{6 ^{2}} = 1

\frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{1 3 ^{2}} = 1

What is the foci (x^2)/(25)+(y^2)/(21)=1 ?
The foci (x^2)/(25)+(y^2)/(21)=1 is (2,0),(-2,0)