What is the foci (x^2)/(99)+(y^2)/(225)=1 ?

The foci (x^2)/(99)+(y^2)/(225)=1 is (0,3sqrt(14)),(0,-3sqrt(14))

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foci (x^2)/(99)+(y^2)/(225)=1

foci

\frac{x ^{2}}{99} + \frac{y ^{2}}{225} = 1

(0, 314), (0, - 314)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{99} + \frac{y ^{2}}{225} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 15, a = 311

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 5^{2} - (311)^{2} : 314

(0, 0 + 314), (0, 0 - 314)

Refine

(0, 314), (0, - 314)

4 x^{2} + 9 y^{2} = 1

25 x^{2} + 16 y^{2} - 100 x - 300 = 0

\frac{( x - 2 ) ^{2}}{2} + \frac{( y - 1 ) ^{2}}{8} = 1

9 x^{2} + 4 y^{2} = 25

4 x^{2} + 9 y^{2} + 24 x - 36 y + 36 = 0

What is the foci (x^2)/(99)+(y^2)/(225)=1 ?
The foci (x^2)/(99)+(y^2)/(225)=1 is (0,3sqrt(14)),(0,-3sqrt(14))