What is the foci (x^2}{64}+\frac{y^2)/1 =1 ?

The foci (x^2}{64}+\frac{y^2)/1 =1 is (3sqrt(7),0),(-3sqrt(7),0)

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foci (x^2}{64}+\frac{y^2)/1 =1

foci

\frac{x ^{2}}{64} + \frac{y ^{2}}{1} = 1

(37, 0), (- 37, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{64} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 1^{2} : 37

(0 + 37, 0), (0 - 37, 0)

Refine

(37, 0), (- 37, 0)

\frac{x ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

\frac{( x + 2 ) ^{2}}{10} + \frac{( y - 5 ) ^{2}}{2} = 1

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

4 x^{2} + 25 y^{2} - 100 = 0

25 x^{2} + 9 y^{2} - 225 = 0

What is the foci (x^2}{64}+\frac{y^2)/1 =1 ?
The foci (x^2}{64}+\frac{y^2)/1 =1 is (3sqrt(7),0),(-3sqrt(7),0)