What is the foci ((x)^2)/9+(y^2)/4 =1 ?

The foci ((x)^2)/9+(y^2)/4 =1 is (sqrt(5),0),(-sqrt(5),0)

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foci ((x)^2)/9+(y^2)/4 =1

foci

\frac{( x ) ^{2}}{9} + \frac{y ^{2}}{4} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} - 2^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

4 x^{2} + y^{2} + 40 x + 6 y + 95 = 0

\frac{x ^{2}}{1} + \frac{y ^{2}}{4} = 1

\frac{( y + 4 ) ^{2}}{24} + \frac{( x - 3 ) ^{2}}{12} = 1

4 x^{2} + 16 y^{2} - 64 = 0

\frac{x ^{2}}{20} + \frac{y ^{2}}{16} = 1

What is the foci ((x)^2)/9+(y^2)/4 =1 ?
The foci ((x)^2)/9+(y^2)/4 =1 is (sqrt(5),0),(-sqrt(5),0)