What is the foci ((x)^2}{25}+\frac{(y)^2)/9 =1 ?

The foci ((x)^2}{25}+\frac{(y)^2)/9 =1 is (4,0),(-4,0)

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foci ((x)^2}{25}+\frac{(y)^2)/9 =1

foci

\frac{( x ) ^{2}}{25} + \frac{( y ) ^{2}}{9} = 1

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} - 3^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

1 x^{2} + 4 y^{2} + 10 x + 9 y - 10 = 0

\frac{( x + 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{25} = 1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

x^{2} + 16 y^{2} - 64 = 0

18 x^{2} + 24 x + 12 y^{2} - 12 y = 1

What is the foci ((x)^2}{25}+\frac{(y)^2)/9 =1 ?
The foci ((x)^2}{25}+\frac{(y)^2)/9 =1 is (4,0),(-4,0)