What is the foci (x^2)/1+(y^2)/(64)=1 ?

The foci (x^2)/1+(y^2)/(64)=1 is (0,3sqrt(7)),(0,-3sqrt(7))

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foci (x^2)/1+(y^2)/(64)=1

foci

\frac{x ^{2}}{1} + \frac{y ^{2}}{64} = 1

(0, 37), (0, - 37)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{1} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} - 1^{2} : 37

(0, 0 + 37), (0, 0 - 37)

Refine

(0, 37), (0, - 37)

\frac{( x ) ^{2}}{13} + \frac{y ^{2}}{4} = 1

\frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{1 x ^{2}}{16} + \frac{y ^{2}}{9} = 1

\frac{( x - 4 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{16} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1

What is the foci (x^2)/1+(y^2)/(64)=1 ?
The foci (x^2)/1+(y^2)/(64)=1 is (0,3sqrt(7)),(0,-3sqrt(7))