What is the foci ((x-1)^2)/(81)+((y-7)^2)/(45)=1 ?

The foci ((x-1)^2)/(81)+((y-7)^2)/(45)=1 is (7,7),(-5,7)

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foci ((x-1)^2)/(81)+((y-7)^2)/(45)=1

foci

\frac{( x - 1 ) ^{2}}{81} + \frac{( y - 7 ) ^{2}}{45} = 1

(7, 7), (- 5, 7)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{81} + \frac{( y - 7 ) ^{2}}{45} = 1 :

Ellipse with center

(h, k) = (1, 7), a = 9, b = 35

(1 + c, 7), (1 - c, 7)

Compute

c :

c = 9^{2} - (35)^{2} : 6

(1 + 6, 7), (1 - 6, 7)

Refine

(7, 7), (- 5, 7)

3 x^{2} + 7 y^{2} = 21

x^{2} + y^{2} + 10 x - 6 y + 33 = 0

\frac{( x - 2 ) ^{2}}{36} + \frac{( y - 6 ) ^{2}}{4} = 1

4 x^{2} + y^{2} - 48 x + 4 y + 48 = 0

7 x^{2} = 14 - 2 y^{2}

What is the foci ((x-1)^2)/(81)+((y-7)^2)/(45)=1 ?
The foci ((x-1)^2)/(81)+((y-7)^2)/(45)=1 is (7,7),(-5,7)