What is the foci 16x^2+4y^2-64=0 ?

The foci 16x^2+4y^2-64=0 is (0,2sqrt(3)),(0,-2sqrt(3))

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foci 16x^2+4y^2-64=0

foci

16 x^{2} + 4 y^{2} - 64 = 0

(0, 23), (0, - 23)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

16 x^{2} + 4 y^{2} - 64 = 0 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} - 2^{2} : 23

(0, 0 + 23), (0, 0 - 23)

Refine

(0, 23), (0, - 23)

\frac{( x + 6 ) ^{2}}{7} + \frac{( y - 3 ) ^{2}}{16} = 1

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{36} + \frac{8 y ^{2}}{81} = 1

x^{2} + 3 y^{2} + 8 x + 9 y - 14 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{13} = 1

What is the foci 16x^2+4y^2-64=0 ?
The foci 16x^2+4y^2-64=0 is (0,2sqrt(3)),(0,-2sqrt(3))