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Popular >

foci x^2+(y^2)/5 =1

Solution

foci

x^{2} + \frac{y ^{2}}{5} = 1

Solution

(0, 2), (0, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

x^{2} + \frac{y ^{2}}{5} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 1^{2} : 2

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

Popular Examples

foci x^2+4y^2+4x=0 foci

x^{2} + 4 y^{2} + 4 x = 0

foci ((x-1)^2)/6+((y+2)^2)/(18)=1 foci

\frac{( x - 1 ) ^{2}}{6} + \frac{( y + 2 ) ^{2}}{18} = 1

foci ((x+11)^2)/(100)+((y-4)^2)/(19^2)=1 foci

\frac{( x + 11 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{1 9 ^{2}} = 1

foci ((x+6)^2}{18}+\frac{(y+3)^2)/9 =1 foci

\frac{( x + 6 ) ^{2}}{18} + \frac{( y + 3 ) ^{2}}{9} = 1

foci y^2+x^2=100 foci

y^{2} + x^{2} = 100

Frequently Asked Questions (FAQ)

What is the foci x^2+(y^2)/5 =1 ?
The foci x^2+(y^2)/5 =1 is (0,2),(0,-2)