What is the foci 9x^2+25y^2+18x-50y=191 ?

The foci 9x^2+25y^2+18x-50y=191 is (3,1),(-5,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 9x^2+25y^2+18x-50y=191

foci

9 x^{2} + 25 y^{2} + 18 x - 50 y = 191

(3, 1), (- 5, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 18 x - 50 y = 191 :

Ellipse with center

(h, k) = (- 1, 1), a = 5, b = 3

(- 1 + c, 1), (- 1 - c, 1)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 1 + 4, 1), (- 1 - 4, 1)

Refine

(3, 1), (- 5, 1)

\frac{9}{1} x^{2} + (\frac{9 y}{9})^{2} = 9

4 x^{2} + 16 y^{2} - 4 x - 32 y + 1 = 0

\frac{( x - 1 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{5100} = 1

\frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1

(x + 4)^{2} + 9 (y - 3)^{2} = 81

What is the foci 9x^2+25y^2+18x-50y=191 ?
The foci 9x^2+25y^2+18x-50y=191 is (3,1),(-5,1)