What is the foci (x^2)/(81)+(y^2)/(225)=1 ?

The foci (x^2)/(81)+(y^2)/(225)=1 is (0,12),(0,-12)

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foci (x^2)/(81)+(y^2)/(225)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{225} = 1

(0, 12), (0, - 12)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{225} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 15, a = 9

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 5^{2} - 9^{2} : 12

(0, 0 + 12), (0, 0 - 12)

Refine

(0, 12), (0, - 12)

\frac{( x + 4 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{36} = 1

- \frac{2}{3} y^{2} = (x - 4) (x - 1)

\frac{x ^{2}}{5} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{8} = 1

What is the foci (x^2)/(81)+(y^2)/(225)=1 ?
The foci (x^2)/(81)+(y^2)/(225)=1 is (0,12),(0,-12)