What is the foci 4x^2+25y^2+40x-150y+225=0 ?

The foci 4x^2+25y^2+40x-150y+225=0 is (-5+sqrt(21),3),(-5-sqrt(21),3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 4x^2+25y^2+40x-150y+225=0

foci

4 x^{2} + 25 y^{2} + 40 x - 150 y + 225 = 0

(- 5 + 21, 3), (- 5 - 21, 3)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 25 y^{2} + 40 x - 150 y + 225 = 0 :

Ellipse with center

(h, k) = (- 5, 3), a = 5, b = 2

(- 5 + c, 3), (- 5 - c, 3)

Compute

c :

c = 5^{2} - 2^{2} : 21

(- 5 + 21, 3), (- 5 - 21, 3)

\frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{25}{16}} = 1

2 x^{2} + 3 y^{2} + 4 x - 1 = 0

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{9} = 1

\frac{( x + 5 ) ^{2}}{20} + \frac{( y - 6 ) ^{2}}{11} = 1

What is the foci 4x^2+25y^2+40x-150y+225=0 ?
The foci 4x^2+25y^2+40x-150y+225=0 is (-5+sqrt(21),3),(-5-sqrt(21),3)