What is the foci ((x-1)^2)/(45)+((y-7)^2)/(81)=1 ?

The foci ((x-1)^2)/(45)+((y-7)^2)/(81)=1 is (1,13),(1,1)

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foci ((x-1)^2)/(45)+((y-7)^2)/(81)=1

foci

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 7 ) ^{2}}{81} = 1

(1, 13), (1, 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 7 ) ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (1, 7), b = 9, a = 35

(1, 7 + c), (1, 7 - c)

Compute

c :

c = 9^{2} - (35)^{2} : 6

(1, 7 + 6), (1, 7 - 6)

Refine

(1, 13), (1, 1)

\frac{x ^{2}}{67} + \frac{y ^{2}}{57} = 1

4 x^{2} + 16 y^{2} = 64

\frac{( x + 4 ) ^{2}}{22} + \frac{( y + 3 ) ^{2}}{26} = 1

+ 4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

16 (x - 4)^{2} + 25 (y + 2)^{2} = 400

What is the foci ((x-1)^2)/(45)+((y-7)^2)/(81)=1 ?
The foci ((x-1)^2)/(45)+((y-7)^2)/(81)=1 is (1,13),(1,1)