What is the foci 16x^2+25y^2+100y=300 ?

The foci 16x^2+25y^2+100y=300 is (3,-2),(-3,-2)

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foci 16x^2+25y^2+100y=300

foci

16 x^{2} + 25 y^{2} + 100 y = 300

(3, - 2), (- 3, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} + 100 y = 300 :

Ellipse with center

(h, k) = (0, - 2), a = 5, b = 4

(0 + c, - 2), (0 - c, - 2)

Compute

c :

c = 5^{2} - 4^{2} : 3

(0 + 3, - 2), (0 - 3, - 2)

Refine

(3, - 2), (- 3, - 2)

\frac{( x - 5 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x + 1 ) ^{2}}{25} + \frac{y ^{2}}{16} = 1

(\frac{x}{2.5})^{2} + (\frac{y}{3})^{2} = 1

9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0

25 (x - 1)^{2} + 9 (y + 4)^{2} = 225

What is the foci 16x^2+25y^2+100y=300 ?
The foci 16x^2+25y^2+100y=300 is (3,-2),(-3,-2)