What is the foci 64x^2+100y^2-256x+200y-6044=0 ?

The foci 64x^2+100y^2-256x+200y-6044=0 is (8,-1),(-4,-1)

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foci 64x^2+100y^2-256x+200y-6044=0

foci

64 x^{2} + 100 y^{2} - 256 x + 200 y - 6044 = 0

(8, - 1), (- 4, - 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

64 x^{2} + 100 y^{2} - 256 x + 200 y - 6044 = 0 :

Ellipse with center

(h, k) = (2, - 1), a = 10, b = 8

(2 + c, - 1), (2 - c, - 1)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(2 + 6, - 1), (2 - 6, - 1)

Refine

(8, - 1), (- 4, - 1)

\frac{( x + 10 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{5} = 1

16 x^{2} + 36 y^{2} = 576

1 x^{2} + 3 y^{2} + 9 x + 8 y - 14 = 0

\frac{( x + 3 ) ^{2}}{6 ^{2}} + \frac{( y + 7 ) ^{2}}{2 ^{2}} = 1

\frac{( x + 5 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

What is the foci 64x^2+100y^2-256x+200y-6044=0 ?
The foci 64x^2+100y^2-256x+200y-6044=0 is (8,-1),(-4,-1)