What is the foci (((x+7)^2))/9+(((y-4)^2))/7 =1 ?

The foci (((x+7)^2))/9+(((y-4)^2))/7 =1 is (-7+sqrt(2),4),(-7-sqrt(2),4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (((x+7)^2))/9+(((y-4)^2))/7 =1

foci

\frac{( ( x + 7 ) ^{2} )}{9} + \frac{( ( y - 4 ) ^{2} )}{7} = 1

(- 7 + 2, 4), (- 7 - 2, 4)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 7 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{7} = 1 :

Ellipse with center

(h, k) = (- 7, 4), a = 3, b = 7

(- 7 + c, 4), (- 7 - c, 4)

Compute

c :

c = 3^{2} - 7^{2} : 2

(- 7 + 2, 4), (- 7 - 2, 4)

9 x^{2} + y^{2} = 1

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{25} = 1

9 (x - 5)^{2} + 4 (y + 2)^{2} = 36

x^{2} \frac{1}{2} + y^{2} \frac{1}{4} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{3} = 1

What is the foci (((x+7)^2))/9+(((y-4)^2))/7 =1 ?
The foci (((x+7)^2))/9+(((y-4)^2))/7 =1 is (-7+sqrt(2),4),(-7-sqrt(2),4)