What is the foci 2x^2-8x+3y^2+6y+5=0 ?

The foci 2x^2-8x+3y^2+6y+5=0 is (3,-1),(1,-1)

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foci 2x^2-8x+3y^2+6y+5=0

foci

2 x^{2} - 8 x + 3 y^{2} + 6 y + 5 = 0

(3, - 1), (1, - 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

2 x^{2} - 8 x + 3 y^{2} + 6 y + 5 = 0 :

Ellipse with center

(h, k) = (2, - 1), a = 3, b = 2

(2 + c, - 1), (2 - c, - 1)

Compute

c :

c = 3^{2} - 2^{2} : 1

(2 + 1, - 1), (2 - 1, - 1)

Refine

(3, - 1), (1, - 1)

36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472

\frac{x ^{2}}{81} + \frac{y ^{2}}{56} = 1

x^{2} - 4 x + 9 y^{2} + 54 y + 4 = 0

x^{2} + 4 x + 4 y^{2} - 8 y + 4 = 0

x^{2} + 5 y^{2} - 2 x + 10 y = - 1

What is the foci 2x^2-8x+3y^2+6y+5=0 ?
The foci 2x^2-8x+3y^2+6y+5=0 is (3,-1),(1,-1)