What is the foci 25x^2+16y^2-150x-32y-159=0 ?

The foci 25x^2+16y^2-150x-32y-159=0 is (3,4),(3,-2)

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foci 25x^2+16y^2-150x-32y-159=0

foci

25 x^{2} + 16 y^{2} - 150 x - 32 y - 159 = 0

(3, 4), (3, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 16 y^{2} - 150 x - 32 y - 159 = 0 :

Ellipse with center

(h, k) = (3, 1), b = 5, a = 4

(3, 1 + c), (3, 1 - c)

Compute

c :

c = 5^{2} - 4^{2} : 3

(3, 1 + 3), (3, 1 - 3)

Refine

(3, 4), (3, - 2)

\frac{( x + 6 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

9 x^{2} + y^{2} + 18 x - 4 y + 4 = 0

\frac{x ^{2}}{32} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{100} + \frac{( y - 6 ) ^{2}}{64} = 1

6 x^{2} + 9 y^{2} - 18 y - 45 = 0

What is the foci 25x^2+16y^2-150x-32y-159=0 ?
The foci 25x^2+16y^2-150x-32y-159=0 is (3,4),(3,-2)