What is the foci 25x^2+y^2-4y-21=0 ?

The foci 25x^2+y^2-4y-21=0 is (0,2+2sqrt(6)),(0,2-2sqrt(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 25x^2+y^2-4y-21=0

foci

25 x^{2} + y^{2} - 4 y - 21 = 0

(0, 2 + 26), (0, 2 - 26)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + y^{2} - 4 y - 21 = 0 :

Ellipse with center

(h, k) = (0, 2), b = 5, a = 1

(0, 2 + c), (0, 2 - c)

Compute

c :

c = 5^{2} - 1^{2} : 26

(0, 2 + 26), (0, 2 - 26)

16 x^{2} + 25 y^{2} - 64 x + 150 y = - 279

\frac{( x - 12 ) ^{2}}{100} + \frac{( y + 7 ) ^{2}}{36} = 1

\frac{x ^{2}}{0.38 4 ^{2}} + \frac{y ^{2}}{0.375 8 ^{2}} = 1

4 x^{2} + y^{2} + 6 y + 5 = 0

9 (x + 2)^{2} + (y + 1)^{2} = 1

What is the foci 25x^2+y^2-4y-21=0 ?
The foci 25x^2+y^2-4y-21=0 is (0,2+2sqrt(6)),(0,2-2sqrt(6))