What is the foci 2x^2+3y^2+4x-6y-1=0 ?

The foci 2x^2+3y^2+4x-6y-1=0 is (0,1),(-2,1)

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foci 2x^2+3y^2+4x-6y-1=0

foci

2 x^{2} + 3 y^{2} + 4 x - 6 y - 1 = 0

(0, 1), (- 2, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

2 x^{2} + 3 y^{2} + 4 x - 6 y - 1 = 0 :

Ellipse with center

(h, k) = (- 1, 1), a = 3, b = 2

(- 1 + c, 1), (- 1 - c, 1)

Compute

c :

c = 3^{2} - 2^{2} : 1

(- 1 + 1, 1), (- 1 - 1, 1)

Refine

(0, 1), (- 2, 1)

\frac{x ^{2}}{15} + \frac{( y - 5 ) ^{2}}{20} = 1

x^{2} + 9 y^{2} - 8 x + 18 y - 11 = 0

4 x^{2} + 36 y^{2} - 24 x - 288 y + 611 = 0

\frac{( x - 1 ) ^{2}}{12} + \frac{( y - 2 ) ^{2}}{8} = 1

\frac{( x + 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

What is the foci 2x^2+3y^2+4x-6y-1=0 ?
The foci 2x^2+3y^2+4x-6y-1=0 is (0,1),(-2,1)